Homework Statement
http://img236.imageshack.us/img236/5369/physxn6.png [Broken]
Homework Equations
F = IL x B
F = QV x B
The Attempt at a Solution
Since I know I, L, Q, and V, I tried to work those into the two force equations... but I got no where. They dont give me B.
Work is the change in kinetic energy. KEf - KEi, but since its at rest in the beginning, its KEf - 0, which is just w=KEf. Remember to consider rotational kinetic energy, because it is rotating. Good luck to you both!
they give you 118 rpm. You have to convert that to angular velocity using factor label.
You have time and final angular velocity, so you can find angular acc. using Vf = Vi + at where Vf=final angular vel, Vi = initial angular vel (which is 0 in this case), a=angular acc, and t=time.
then...
well then i guess your initial approach is correct. the equation I gave might not work cuz i didnt read the part that said "avg velocity". I think your -61 is correct
I dont know why they gave you impulse, you can solve the problem with this equation:
Vf = Vi + at
where Vf=final velocity, Vi=initial velocity, a=acc. and t=time.
Remember - the acc. is .8/.462 because F=ma, so a=F/m.
Good luck!
Newton's 3rd law tells us that when you punch the wall, the wall punches back equally. In other words, with equal force. In other words, you don't punch the block with any more force than the wall punches you with. In other words, your punch's force and the wall's punching force are equal.
So...
Homework Statement
An object is thrown downward with an initial
speed of 4 m/s from a height of 99 m above the
ground. At the same instant, a second object
is propelled vertically from ground level with
a speed of 25 m/s.
The acceleration of gravity is 9.8 m/s^2.
At what height above...
well a is -9.8 because of gravity.
Vi is 2.6, but its the opposite direction of falling. So what do I do with it?
d is 19 m.
I dont know how to use that equation because the Velocity is upward, but the object is falling DOWN.
First of all, you dont need to make a theoretical velocity because they cancel out in the end. Now...
(2)(1/2 I w^2) + (1/2 m v^2)
(2)(1/2) is 1. You know that w=v/r, so plug in v/r for w, and you get
I(v/r)^2 + (1/2 m v^2)
You know I, r, and m, so you get
((.08)V^2)/.3 + (1/2)(74)V^2
Do...
Total KE in this case is 2KEr + KEt, where KEr is rotational kinetic energy and KEt is translational/linear kinetic energy. Because the bike itself as a whole is moving linearly, it has KEt. And since there are two wheels, there is KEr - but 2KEr because of the two wheels.
So the total...
Homework Statement
The position of a toy locomotive moving on a
straight track along the x-ais is given by the
equation
x = t^6 - 6t^2 + 9t
where x is in meters and t is in seconds.
The net force on the locomotive is equal to
zero when t is equal to _______?
Answer in units of...
Homework Statement
A Hot air balloon is traveling vertically up-
ward at a constant speed of 2.6 m/s. When
it is 19 m above the ground, a package is
released from the balloon.
The acceleration of gravity is 9.8 m/s^2.
After it is released, for how long is the
package in the air? Answer...
Homework Statement
An object is thrown downward with an initial speed of 4 m/s from a height of 99m above the ground. At the same instant, a second object is propelled vertically from the ground level with a speed of 25 m/s.
The acceleration of gravity is 9.8 m/s^2.
At what height above the...